Equations..

[Edward Hernandez R]

>   There may be a factor of 1000 problem here.  Someone please
>   check the following math!
>   _
>   R = 8.3 J/(mole*K)
>       _
>   R = R/M = { 8.3 J/(mole*K) } / { 29 g/mole }  = 0.287 J/(g*K)
>                                                 = 0.287 kJ/(kg*K)

Your math is correct, but I posted the wrong units in the formula.
R is actually in units of J/(kg*K), not kJ/(kg*K) as I first posted.

Substitue "R=287 J/(kg*K)" instead of "R=287 kJ/(kg*K)" and the units
will work out in the formula as originally posted. Gee, you guys are
sharp!

Ed Hernandez
Ford Motor Company
ehernan3 at ed8719.pto.ford.com