Hydrualic pressure to HP formula

Andrew Rabbitt AERabbitt at rce.ricardo.com
Wed Jun 11 15:52:41 GMT 1997


In metric it's easy:

24gal/min = 0.00154 m^3/s;  2300psi = 15.847MPa

therefore Power = Volume Flow * Pressure (drop)

Assuming all 2300psi is lost across your actuator, then

	P = 0.00154 * 15.847 = 24.4kW (32.7hp)

Obviously not all the pressure will be converted into work due to fluid
entry and exit losses, thus you can stuff an efficiency factor in there.
It will be an inverse function of your flow rate.

Note that this is a derivative of the Work=Force*Distance =>
Power=Force*Vel.

Andrew Rabbitt

> ----------
> From: 	Dan[SMTP:DanLlwln at ix.netcom.com]
> Sent: 	11 June 1997 14:42
> To: 	diy_efi at coulomb.eng.ohio-state.edu
> Subject: 	Hydrualic pressure to HP formula
> 
> What's formula for converting hydraulic pressure into horspower?  For
> instance, at 24 Gallons/Min @ 2300 PSI, what's the equivalent
> horsepower?  
> 
> Thanks,
> 
> Dan L
> 



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