Hydrualic pressure to HP formula

[Ken Mayer]

On Wed, 11 Jun 1997, Andrew Rabbitt wrote:

> In metric it's easy:
> 
> 24gal/min = 0.00154 m^3/s;  2300psi = 15.847MPa
> 
> therefore Power = Volume Flow * Pressure (drop)

Wrong.  You must also consider the density of the liquid, and the head
loss.  Head loss is not pressure drop.
> 
> Note that this is a derivative of the Work=Force*Distance =>
> Power=Force*Vel.

Your derivation is wrong.

Kenneth Mayer, P.E.