Injector Driver Module

[Jose Rodriguez]

Gene, thanks for your response.
  How did you obtain the ~40% number? Was that by doing (0.5)*(0.85)=42.5%?

  Even if I use 40% instead of 85%, I am still in trouble. Power per driver (at 16V) is (14.5W)*(0.4) = 5.8W; total for eight injector drivers: 46.4W.

  I just can not see how the OEM manufacturers can dissipate that much heat. I have seen an injector module from Ford, that I estimate would not be able to dissipate more than 20W (at 125C ambient), so there must be something else I am missing here.

  Does anyone have a number of the power dissipation of a typical peak and hold injector module? (4A peak, 1A hold, 8 injectors).


mrvette wrote:
>IF   I read your analysis correctly....you forgot that is a 4 cycle engine...so
the on time is only ~40%  on a real time basis....NO?   GENE

Jose Rodriguez wrote:
> 
>   I am designing an injector driver module. I would like your input, to see if my calculations are correct, particularly in my assumption that all eight injectors could be on at the same time, for up to 85% duty cycle. Thanks in advance for your answers!
> 
>   The current specs I have are:
> 
>   Eight injectors.
>   Injector coil resistance: 1.5 ohms (it could also be 2.3 ohms)
>   Injector current: 4A peak, 1A hold.
>   Duty cycle: up to 80..85%
>   Operating ambient temp: -40C..125C
>   Operating voltage: 4.5V to 16V.
> 
>   I did some calculations, to estimate how much power would I need to dissipate, worst case, ASSUMING ALL EIGHT INJECTORS COULD BE ON, FOR 85% OF THE TIME (is this assumption correct?)
> 
>   First, I set Vbatt=14V. In order to have 4A circulating, the driver's output voltage would be (14-4*1.5)=8V. Injector's coil voltage = (14-8) = 6V.
>   Instantaneous power at the driver: (8V)*(4A) = 32W. Instantaneous power thru injector's coil: (6V)*(4A) = 24W.
>   The 4A will only circulate for a brief period of time, so average power over one cycle will be much less.
> 
>   One amp, sustaining, automatically means (14*1)=14W have to be dissipated between the injector driver and the injector coil (100% duty cycle).
>   In order to have the 1A sustaining, the driver's output voltage would be (14-1*1.5)=12.5V. Injector's voltage =(14-12.5) = 1.5V.
>   Inst. power at driver: (12.5V)*(1A) = 12.5W. Inst power at injector: (1.5V)*(1A) = 1.5W. (total=14W, as predicted).
> 
>   Thus, since the Duty Cycle can be up to 85%, and disregarding the initial 4A power peak, and the switching power losses, then the average power for each injector driver is (12.5W)*(0.85) = 10.625W. The average power for each injector coil is (1.5W)*(0.85)=1.275W.
> 
>   If all 8 injectors could be on 85% of the time, then the maximum average power at Vbatt=14V (again, disregarding some power losses) would be (8)*(10.625W) = 85W at the injector driver side. Obviously, at 16V the power dissipation would be higher (98.6W!).
> 
>   As you can imagine, dissipating 98.6W+ into an under-the-hood ambient of 125C, with no expected air flow, is a formidable task. The heatsink's surface temperature should not be allowed to go above 150C; that would mean the thermal resistance from the heatsink to ambient would be (150-125)/98.6 = 0.25C/W. I can not see any feasible heatsink doing that, without the need for forced cooling.