Supercharger info

[Walter Petermann]

Dan,
there was an idea to use the period between ignition pulses
to control the charging time of the cap. Haven't looked at
this in a few weeks but I seem to remember that this gave a 
log answer (log air - log rpm) and would have to be reconverted (antilog) maybe using another 555. 

  Walter 

Dan Zorde wrote:
> 
> Sounds logical, but how do you divide a voltage output by a frequency signal ?
>  Do you turn the rpm into a voltage first ?
> 
> Dan     dzorde at soanar.com.au
> 
> On Wednesday, 12 August, 1998 1:39 PM, Walter Petermann
> [SMTP:corsaro at brokersys.com] wrote:
> > Mike,
> > I think what he's saying is this:
> >
> > Say the MAF output is read as kg/min of air then
> >
> > kg/min (air)*14.7= kg/min (fuel)
> >
> > but what's needed is kg/rev of fuel to get injector on time. Deviding
> > kg/min (fuel) by rpm gives kg/rev (fuel). Or, MAF reading needs to
> > be devided by rpm.
> >
> >  Walter
> >
> > Mike Morrin wrote:
> > >
> > > >Chris Morriss wrote:
> > > >>  Imagine that the engine is
> > > >> loaded such that it requires the same amount of fuel per revolution at
> > > >> 6000 rpm as it does at 2000 rpm.  The MAF at 6000 rpm is going to be
> > > >> roughly 3 times as much as at 2000,
> > >
> > > Are you saying that the air/fuel ratio is varying in proportion to RPM?
> > > smells fishy to me...
> > >
> > > regards,
> > >
> > > Mike Morrin