Need more fuel 2

[David Piper]

It doesn't matter. the volume units cancel.
6.15 / 3875 = 7.21 / 4540

At 09:06 AM 3/23/98 -0500, you wrote:
>> 
>> 19pph X 8 / .5 lb /BHP-hr BSFC = 304 HP
>> 
>> Increase fuel press to 60 psig:
>> 
>> 304 X sq rt(60/40) = 372 HP potential
>> 
>> inj cc/min = pph / 6.15 lb/gal / 3875 cc/gal / 60 s = 10.5 X pph rate
>
>
>note this is for an American gallon not Brit (Imp) gal
>Imp Gal is 7.21 lbs 
>or 4540 cc/Gal
>
>Clive 
>> 
>> TurboDave
>> 
>> At 06:08 PM 3/22/98 -0800, you wrote:
>> >Oops, forgot one question before.  I have never had the car dynoed so I have
>> >no idea of the hp I'm putting out. But now that I know the injectors are
>> >fired in pairs for 12.85ms @ a fuel pressure of (36psi or 38 psi, 305 chev
>> >??) using an injector size of 19 lb/hr (?? 305 chev, Bosch injectors),
>> >running at 100%.
>> >
>> >What is the formula for calculating the theoretical hp from your available
>> >fuel ?
>> >
>> >Ta
>> >
>> >Dan     dzorde at geocities.com
>> >
>> >
>> 
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