Misc ?? EFI

[Greg Hermann]

>-----Original Message-----
>From: Scot Sealander <Sealand at clarityconnect.com>
>To: diy_efi at efi332.eng.ohio-state.edu <diy_efi at efi332.eng.ohio-state.edu>
>Date: Saturday, November 21, 1998 6:05 PM
>Subject: Re: Misc ?? EFI
>
>
>snip
>
>>
>>Take this example.  If you know the amount (mass) of air that is in the
>>cylinder and divide that by the desired AFR, you get the amount of fuel
>>needed for that cylinder.
>
>For figuring that mass, (correct me if I'm wrong):
>Engine displacement * RPM/no of cyl * VE

divide by 2, cuz it is a four stroke, divide by 1728 (cubic inches per
cubic foot), multiply by the density of air in pounds per cubic foot (about
.075 at sea level), and multiply by 60 (minutes per hour). Ya gotta get the
units to equate as well as the numbers before the numbers can make any
sense.

Regards, Greg
>
>so that product divided by 14.7= amount of fuel needed (#/hr ?)
>That can't be right, I'm missing something there in the first
>equation, no mention of #s

(It is once the units balance.)