TORK???

[Raymond C Drouillard]

On Fri, 5 Feb 1999 00:29:24 EST A70Duster at aol.com writes:
>In a message dated 2/4/1999 8:00:22 PM Mountain Standard Time, 
>bearbvd at sni.net
>writes:
>
><< Doesn't matter what the speeds are doing, input torque, output
> torque and reaction torque must sum to zero.  >>
>
>
>Or mass times ACCELERATION, which is why we are all here!!!!!
>

Yes, you have to include the torque due to the acceleration of the
system.  That torque isn't totally insignificent, but it's close.  I
believe that the torque due to acceleration is (d omega / dt) * mass *
gyration radius.  I could be wrong - I don't have a reference handy, nor
did I take the time to derive it.

Ray Drouillard

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