multimeter advice needed

[Raymond C Drouillard]

>The heart of the Hall effect sensor is usually a chunk of silicon. A
small
>current is passed through the semiconductor. When a magnetic field is
>applied perpendicular to the direction of current flow some of the
charge
>carriers are deflected in direction quadrature to the current and the
>magnetic field. Eventually equilibrium is reached when the electric
field
>(caused by the displaced charge carriers) equals the force caused by the
>magnetic field. Given the dimension of the silicon slab and charge
carrier
>density we can calculate the electric field for a given voltage
generated.
>We can therefore calculate the relationship between the applied magnetic
>field and the voltage generated.

Or, we can get an ammeter and a voltmeter and plot the sensor output
voltage against the current.  Why calculate when you can measure?

Ray

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