Ignition only

[Bruce Plecan]

Ya, well meaning and good but.
Your trying to expalin things as a DCv,  and it's just not that way.
This has to "balance" on both sides, doesn't apply.

Does any one know of a on-line picture or scan of a scope pattern of a plug
firing?.
If we all had some common reference maybe I could better explain what the
scope is actually displaying and then folks might get a better grasp of
things and we can get off of this DC silliness
Bruce




From: "James Ballenger" <vtjballeng at yifan.net>
> I have a non-EE explanation.  Based on Ohms law, which should apply
> here.  Let's assume the coil has the ability to only put out a set
amperage
> per fire and that amperage has to go across the spark plug on each side.
> Use V=IR.  The cylinder with higher pressure will have a higher voltage
for
> the same amperage.  The cylinder with the lower pressure will have a lower
> voltage for the same amperage.
> As an fictional example:
> Combustion side.  40,000V = 10000ohms*4amps
> Waste side 5,000V = 1,250ohms*4amps
> Same current passing through both of them... it is just like a
> series circuit with the voltage source in the center as I see it.  If this
> is wrong, please tell me why.
> James Ballenger

> If the
> >combustion end has a high potential, and the waste end has a
> >low potential
> >across the gaps, wouldn't the Amperage be inversely
> >proportional in it's
> >respective cylinder, to the other one? I'm just a Refrigeration
> >Tech/Industrial Electrician here, not an EE. Please, if I'm incorrect,
> >correct me and enlighten us all. Thanks
> >Scott Creech

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