More DIY EGOR

[RDwoo10 at aol.com]

I think that we are in agreement here.  as the temp goes up, the resistance 
goes up.  as resistance goes up we want the current to go down (E=I^2R, AKA 
power).  if the voltage is constant, the current will go down (E=IR), because 
the temp went up.  this will happen by itself.  i guess, now that i think 
about it.  a constant voltage source is sufficient, as long as it does not 
take forever to get back down to temp.  if that is the case then we want to 
move the drive voltage inversely proportional to the temp so that the sensor 
gets back down to temp (or up) fast enough that the sensor is still 
outputting the right thing.  All this w/o making it oscillate wildly.  

BW
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