Supercharger info

[Walter Petermann]

Mike,
I think what he's saying is this:
 
Say the MAF output is read as kg/min of air then

kg/min (air)*14.7= kg/min (fuel) 

but what's needed is kg/rev of fuel to get injector on time. Deviding
kg/min (fuel) by rpm gives kg/rev (fuel). Or, MAF reading needs to
be devided by rpm. 

 Walter 

Mike Morrin wrote:
> 
> >Chris Morriss wrote:
> >>  Imagine that the engine is
> >> loaded such that it requires the same amount of fuel per revolution at
> >> 6000 rpm as it does at 2000 rpm.  The MAF at 6000 rpm is going to be
> >> roughly 3 times as much as at 2000,
> 
> Are you saying that the air/fuel ratio is varying in proportion to RPM?
> smells fishy to me...
> 
> regards,
> 
> Mike Morrin