Problems with Haltech F7 at high RPM's

[Slava]

>stop me any time if i'm wrong....  I am assuming that the injectors fire
>1.5 times per rpm, ie. it takes two revolutions for all cylinders to fire
>once....


You have a 3 cylinder 2 stroke engine, and each  injector must fires every
revolution!

But every injector is independent from ather one. thus one injector fire one
times per turn.


7800 / 60 = 130 pulses per second

1 pulse every 7.692 milliseconds

75% duty cycle is 5.77 milliseconds

FOR  2 STROKE  ENGINE !

Slava.



>
>7800 rpm  *  1.5 cyls....
>
>= 11700 injector pulses per minute....
>
>= 195 pulses per second
>
>= .195 pulses per millisecond
>
>= 1 pulse every 5.128 milliseconds
>
>and you say 5 ms is 75% duty cycle ?
>
>actually 3.846 ms pulse width would be 75% duty cycle at 7800 rpm for a 3
>cylinder 2 stroke engine.....
>
>or am i wrong somewhere.....
>
>
>This would mean the reason for it working on the test bench and not on the
>road would be because of the additional load on the engine.  On the test
>bench with no, or little load, the injector pulse width would not be as
long.
>
>Matthew Harding
>---------------
>
>reply to any of these....
>
>mharding at qonline.com.au
>bernie at ronscomputers.com.au
>bernie at browse-cafe.com.au
>