boost presser and power gain

[Greg Hermann]

>Attended Captain's mast recently for post concerning pressure drop thru
>an
>intercooler, when all christians know pressure drop is BECAUSE of
>intercooler...
>Repeal of gas law was disclosed at that time, for reasons which remind
>me of
>Zenos' - Are you suggesting otherwise?  :)
>
>Regards, Jack

Nope.


Thermo 301 class will convene in three weeks. Tuition will be high.
Prerequisites are knowing that F=ma and that you can't push a rope.

Wanna really have some fun-- lets pretend that we are analyzing the cycle
in a supersonic ram-jet.
Anyone care to guess what the temperatur of a supersonic flow does when you
add heat to it at the combustor??

Regards, Greg
>
>Greg Hermann wrote:
>
>> Boost pressure is not the significant thing. DENSITY is what you need to
>> figure. Mass/hour of air through engine relates directly to HP (or KW)
>> output. Density is a function of both manifold absolute pressure and
>> manifold absolute temperature, based on PV=nRT or PV= rho k T (gas law) (R,
>> k, and  n  and V remain constant for a given gas in a given engine at a
>> given speed, so formula simplifies to PV/T=k (rho) (where rho =density) for
>> a given engine situation. Sorry this is not too clear, e-mail doesn't do
>> subscripts and Greek very well. In British units, Rho=.0762 lbs./cu. ft. at
>> standard temperature and pressure, which are 14.69 psia and 69 degrees F
>> (same as 528.9 degrees Kelvin (absolute). You should be able to do simple
>> ratio calculations based on these numbers and you proposed (or actual)
>> manifold pressure and temperature to arrive at you manifold density. Mass
>> flow of air through engine is equal to displacement times .5 (for a four
>> stroke) times engine speed times manifold density times volumetric
>> efficiency. Depending greatly on engine characteristics, particularly
>> compression ratio, Each 1 pound per hour of air flow through an engine will
>> give in the range of 7 to 8.5 HP of output from a turbocharged engine.