DIY_EFI Digest V4 #85

[Orin Eman]

> >Actaully I think this is how it works.  The reason it multiplies is
> >much simpler, rpmin != rpmout.   The easy model is more like
> >rpmin*torquein = rpmout*torqueout*efficiency.   I don't believe there

That's a power equation - power out = power in * efficiency.

> A manual tranny has a torque reaction when in other than direct drive--you
> are just not aware of it, cuz the bell housing puts it into the engine and
> thence into the motor mounts. OK--consider--when you have a busted motor
> mount with a manual tranny--is the engine more likely to lift up off of it
> in first gear or high gear when you jump the throttle?? Same principle. The
> manual tranny puts its torque reaction into its case via the countershaft
> (layshaft in Brit-speak) bearings when in a gear that multiplies torque.
> There simply HAS GOT to be a third, reaction element for torque to either
> increase or decrease in a transmission, coupling, or torque converter of
> any sort. Doesn't matter what the speeds are doing, input torque, output
> torque and reaction torque must sum to zero. Don't know how else to say it,
> let alone be any more plain about it!!

It's not a statics problem.  You accelerate the oil on one side
Fi = ma with the F coming from the input torque.  You decelerate the oil
on the other side Fo = ma.  

Fi depends on the distance form the center on the converter on the
input side (input torque).  Similarly for Fo on the output side.

I don't see a need for a third reaction element.

Orin.