multimeter advice needed

[Wen Yen Chan]

On Wed, 17 Feb 1999, Raymond C Drouillard wrote:

> 
> >The heart of the Hall effect sensor is usually a chunk of silicon. A
> small
> >current is passed through the semiconductor. When a magnetic field is
> >applied perpendicular to the direction of current flow some of the
> charge
> >carriers are deflected in direction quadrature to the current and the
> >magnetic field. Eventually equilibrium is reached when the electric
> field
> >(caused by the displaced charge carriers) equals the force caused by the
> >magnetic field. Given the dimension of the silicon slab and charge
> carrier
> >density we can calculate the electric field for a given voltage
> generated.
> >We can therefore calculate the relationship between the applied magnetic
> >field and the voltage generated.
> 
> Or, we can get an ammeter and a voltmeter and plot the sensor output
> voltage against the current.  Why calculate when you can measure?
> 
> Ray
> 
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 Hello,

I was just trying to explain how the sensor works from the ground up. 
Rather than calculate the sensitivity, or measure it, I think it would be
even easier to just lookup the sensor's sensitivity in the spec. sheets
:).

Wen