Ignition only

[James Ballenger]

	I have a non-EE explanation.  Based on Ohms law, which should apply
here.  Let's assume the coil has the ability to only put out a set amperage
per fire and that amperage has to go across the spark plug on each side.
Use V=IR.  The cylinder with higher pressure will have a higher voltage for
the same amperage.  The cylinder with the lower pressure will have a lower
voltage for the same amperage.

As an fictional example:
Combustion side.  40,000V = 10000ohms*4amps
Waste side		5,000V = 1,250ohms*4amps

	Same current passing through both of them... it is just like a
series circuit with the voltage source in the center as I see it.  If this
is wrong, please tell me why.

James Ballenger



If the
>combustion end has a high potential, and the waste end has a 
>low potential
>across the gaps, wouldn't the Amperage be inversely 
>proportional in it's
>respective cylinder, to the other one? I'm just a Refrigeration
>Tech/Industrial Electrician here, not an EE. Please, if I'm incorrect,
>correct me and enlighten us all. Thanks
>
>Scott Creech
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