Ignition only

Shannen Durphey shannen at grolen.com
Sat Nov 11 03:11:07 GMT 2000


Cancel that.  I left the book with the good pictures at the shop.
Shannen

Shannen at grolen.com wrote:
> 
> I'll scan some pics when I get to my pc, if no one else comes through.
> 
> DI>Ya, well meaning and good but.
> DI>Your trying to expalin things as a DCv,  and it's just not that way.
> DI>This has to "balance" on both sides, doesn't apply.
> 
> DI>Does any one know of a on-line picture or scan of a scope pattern of a plug
> DI>firing?.
> DI>If we all had some common reference maybe I could better explain what the
> DI>scope is actually displaying and then folks might get a better grasp of
> DI>things and we can get off of this DC silliness
> DI>Bruce
> 
> DI>From: "James Ballenger" <vtjballeng at yifan.net>
> DI>> I have a non-EE explanation.  Based on Ohms law, which should apply
> DI>> here.  Let's assume the coil has the ability to only put out a set
> DI>amperage
> DI>> per fire and that amperage has to go across the spark plug on each side.
> DI>> Use V=IR.  The cylinder with higher pressure will have a higher voltage
> DI>for
> DI>> the same amperage.  The cylinder with the lower pressure will have a lower
> DI>> voltage for the same amperage.
> DI>> As an fictional example:
> DI>> Combustion side.  40,000V = 10000ohms*4amps
> DI>> Waste side 5,000V = 1,250ohms*4amps
> DI>> Same current passing through both of them... it is just like a
> DI>> series circuit with the voltage source in the center as I see it.  If this
> DI>> is wrong, please tell me why.
> DI>> James Ballenger
> 
> DI>> If the
> DI>> >combustion end has a high potential, and the waste end has a
> DI>> >low potential
> DI>> >across the gaps, wouldn't the Amperage be inversely
> DI>> >proportional in it's
> DI>> >respective cylinder, to the other one? I'm just a Refrigeration
> DI>> >Tech/Industrial Electrician here, not an EE. Please, if I'm incorrect,
> DI>> >correct me and enlighten us all. Thanks
> DI>> >Scott Creech
> 
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