Ignition only

[Bruce Plecan]

If you want to take it that way fine,
I thought I was, your reading stuff into what I said,
wanna be that way fine.
Was hoping for a pic to actually show what's going on cause I've tried
explaining it every way I can 4-5x times here.
L8r
Bruce


> Bruce,
> When I posted my message, I said "If this is wrong, please tell me
> why."  You simply told me I am wrong, with no explanation as to why you
> think I am wrong.  Please offer some constructive criticism and tell me
> exactly why this is wrong.  Simply telling me or anyone else they are
wrong
> and further degrading their opinions by calling them silliness and
referring
> to a need for a better grasp on the concept does little to help this
thread
> or anyone's understanding of the subject.  Please tell us why this is DC
> silliness, not just that it is.
> James Ballenger


> >-----Original Message-----
> >From: owner-diy_efi at diy-efi.org [mailto:owner-diy_efi at diy-efi.org]On
> >Behalf Of Bruce Plecan
> >Sent: Friday, November 10, 2000 4:29 PM
> >To: diy_efi at diy-efi.org
> >Subject: Re: Ignition only
> >
> >
> >
> >Ya, well meaning and good but.
> >Your trying to expalin things as a DCv,  and it's just not that way.
> >This has to "balance" on both sides, doesn't apply.
> >
> >Does any one know of a on-line picture or scan of a scope
> >pattern of a plug
> >firing?.
> >If we all had some common reference maybe I could better
> >explain what the
> >scope is actually displaying and then folks might get a better grasp of
> >things and we can get off of this DC silliness
> >Bruce
> >
> >
> >
> >
> >From: "James Ballenger" <vtjballeng at yifan.net>
> >> I have a non-EE explanation.  Based on Ohms law, which should apply
> >> here.  Let's assume the coil has the ability to only put out a set
> >amperage
> >> per fire and that amperage has to go across the spark plug
> >on each side.
> >> Use V=IR.  The cylinder with higher pressure will have a
> >higher voltage
> >for
> >> the same amperage.  The cylinder with the lower pressure
> >will have a lower
> >> voltage for the same amperage.
> >> As an fictional example:
> >> Combustion side.  40,000V = 10000ohms*4amps
> >> Waste side 5,000V = 1,250ohms*4amps
> >> Same current passing through both of them... it is just like a
> >> series circuit with the voltage source in the center as I
> >see it.  If this
> >> is wrong, please tell me why.
> >> James Ballenger
> >
> >> If the
> >> >combustion end has a high potential, and the waste end has a
> >> >low potential
> >> >across the gaps, wouldn't the Amperage be inversely
> >> >proportional in it's
> >> >respective cylinder, to the other one? I'm just a Refrigeration
> >> >Tech/Industrial Electrician here, not an EE. Please, if I'm
> >incorrect,
> >> >correct me and enlighten us all. Thanks
> >> >Scott Creech
> >
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