Ignition only
Gerald Pelnar
wd0fyf at mpks.net
Sat Nov 11 07:04:52 GMT 2000
----- Original Message -----
From: James Ballenger <vtjballeng at yifan.net>
To: <diy_efi at diy-efi.org>
Sent: Friday, November 10, 2000 12:57 PM
Subject: RE: Ignition only
> I have a non-EE explanation. Based on Ohms law, which should apply
> here. Let's assume the coil has the ability to only put out a set
amperage
> per fire and that amperage has to go across the spark plug on each side.
> Use V=IR. The cylinder with higher pressure will have a higher voltage
for
> the same amperage. The cylinder with the lower pressure will have a lower
> voltage for the same amperage.
>
> As an fictional example:
> Combustion side. 40,000V = 10000ohms*4amps
> Waste side 5,000V = 1,250ohms*4amps
>
> Same current passing through both of them... it is just like a
> series circuit with the voltage source in the center as I see it. If this
> is wrong, please tell me why.
>
> James Ballenger
James--
Your basic analasis of the situation is correct, although the details
may not accurate. Rather than assume a set value for current, assume
a set power (IV) from the coil.
I think Bruce mentioned in this thread, the possibility of firing one plug
with the other disconected. This is also true, because of the design of
the DIS. A plate capacitor replaces the missing plug to complete the
circuit.
Gerald Pelnar
wd0fyf at mpks.net
http://www.mpks.net/homepage/wd0fyf/
McPherson, KS
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