reset vector on a 68hc11

[Pat Ford]

Previously, you (David Cooley) wrote:
> At 10:36 AM 6/25/99 -0400, you wrote:
> >Hi all:
> >
> > This may seem like a simple question but here goes, this is the last line 
> >of the 
> >bin file I'm looking at:
> >000003ff0:  60 00 A1 DA A1 F7 60 00  A0 00 A0 00 A0 00 A0 00
   ^^^^^^^^^ should be 7ff0 ( I loaded the file in the middle.. DOOH)
> >
> >the a0's are the reset vector right? is that a relative or absolute jump.
> >ie does the reset jump to 3f58 ( 3ff0 - a0) or to 20a0 ( A0 + 2000)
> 
> Depends...  Reset vector should be at address FFFE-FFFF... is this prom
> mapped so it's address 3FFE-3FFF is actually the processors FFFE-FFFF?
> If not, the reset vectors are contained in onboard ROM or the CPU's
> embedded ROM.
> If this was really the FFFE-FFFF in the CPU, the A000 would be the absolute
> address of the beginning of the reset code.

so then if the eprom is mapped in so the reset vector is at fffe-ffff
I should subtract 7fff from A000 to get the position of the reset code in 
the eprom ( 0x2000) right. What I'm trying to do is get a good asm listing 
and reverse it to C ( I'm working backwards from gcc for 68hc11)


> =========================================================== 
> David Cooley N5XMT Internet: N5XMT at bellsouth.net 
> Packet: N5XMT at KQ4LO.#INT.NC.USA.NA T.A.P.R. Member #7068 
> We are Borg... Prepare to be assimilated! 
> ===========================================================
> 

--
Pat Ford                           email: pford at qnx.com
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