Yet another O2 sensor fakeout trick

[KD6JDJ at aol.com]

>Thinking about trying yet another trick. I just can't leave this one thing
>alone. I would really like to get rid of my 5th injector. The fuel line is
>touching several items on the motor and I am afraid it might chap and
>spring a leak. Also it doesn't look very professional anyway. And the fact
I> am sure the injectors will provide enough fuel if I could just boost the
>pulse rate up a bit.

>Here's my plan.

>Since my pressure switch has three poles, I can wire it up with a resistor
>in parallel.

>When I hit the boost zone, the O2 sensor's output which is either .8 volts
>or .9 volts, however if I place a resistor between this circuit which
>brings the voltage down to .1 volts the computer will think the engine is
>running lean and increase the pulse rate trying to catch up.

>The trick will be to find the right resistance to create such a voltage 
drop. 

>I know there is a formula somewhere. What size resistor do I need to drop
>the voltage from .9 to .1 volts?

>I am also assuming if I need a little more fuel, I can increase the
>resistance some more.

  James
  I'm no wizard in solid state , but I know that almost all silicon diodes 
have a forward voltage drop of about 3/4 volt. So, if you put one in series 
with a circuit drawing current, it will "drop" that voltage. That way you 
wont need to contend with the voltage divider, which will be current 
dependent.

    Jerry