Computing MPH

[Greg Hermann]

At 11:48 AM 8/27/01, Flanagan, Steve wrote:
>SO what would the formula look like?
>
>mph = |G dt  ( the | means integral)
>
>assuming different G (G1 -> Gn) values for all time intervals I think I
>would get the following
>
>MPH = G1^2/2 * t from t0 --> t1 + G2^2/2 * t from t1 --> t2 + G3^2/2 * t
>from t2 --> t3 +
>  ... Gn^2/2 * t from t(n-1) -> tn.
>
>
>How do we scale G's to MPH?  The following does not look correct to me at
>first glance:
>
>1 G = (32 Ft / sec^2) * (1 Mile / 5280 Ft) * (3600^2 sec ^ 2) / Hr ^ 2 =
>78545 Mile / Hr^2
>
>Now I have G's represented as Mile / Hours (Squared), and when multiplying
>each piece of the formula by the time in Hrs) the answer should be left in
>MPH?

Yeah, although I might be more inclined to integrate to feet per second
from the 32.2 G value, and then multiply by 60/88 to convert to MPH---

Greg


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