[Diy_efi] WBO2 and AFR

[gary]

Another 'potential' trick question.

> > Would you not consider a stoich mixture of fuel one
> > that consumes all the available oxygen?

A guarded No.  The reason being stoich implies burning the available 
fuel AND oxygen present.  You can burn whatever available oxygen 
there is, but still have left over fuel looking for their share of oxygen 
molecules.    Still not stoich, but in lieu of above, I prefer to state 
mixture as one that burns what ever fuel is available.  
   
14.7 was chosen as stoich, as this results in the least amount of the 
various components/products of combustion recognized as harmful.  
IOW, a compromise.  

> > If oxygen were rendered from the combustion event then I 
> > would expect there to be sufficient fuel to combust that as 
> > part of the equation.

I'd be more concerned that there is sufficient oxygen present to 
combust the fuel.  IOW, other way around.  

GAS

----- Original Message ----- 
From: "Adam Wade" <espresso_doppio at yahoo.com>
To: <diy_efi at diy-efi.org>
Sent: Thursday, July 07, 2005 11:56 AM
Subject: RE: [Diy_efi] WBO2 and AFR


> --- Michael Richards <michael at fastmail.ca> wrote:
> 
> > Would you not consider a stoich mixture of fuel one
> > that consumes all the available oxygen?
> 
> If combustion is 100% complete, which of course it
> never is in reality.
> 
> > If oxygen were rendered from the combustion event 
> > then I would expect there to be sufficient fuel to
> > combust that as part of the equation.
> 
> And that is correct.  However, there is nothing to
> detect unburned fuel in the exhaust, so there is no
> way to determine how much of the oxygen is truly
> "excess" and how much "belongs" to uncombusted fuel.